The wavelength of light in two liquids - x- and - y- is 3500 - and 7000 - then the critical angle of x relative to y will be

The correct option is C The critical angle C is given by sin(C) = n_2/n_1 = λ_1/λ_2 ⇒ sin(C) = 3500/7000 = 1/2 ⇒ C = 30^∘ nbsp; ...

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Standard X

Physics

Optical Fiber

The wavelengt...

Question

The wavelength of light in two liquids 'x' and 'y' is 3500 Å and 7000 Å, then

the critical angle of x relative to y will be

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Solution

The correct option is C
The critical angle C is given by

$s i n (C) = \frac{n_{2}}{n_{1}} = \frac{λ_{1}}{λ_{2}} \Rightarrow s i n (C) = \frac{3500}{7000} = \frac{1}{2} \Rightarrow C = 30^{\circ}$

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The wavelength of light in two liquids 'x' and 'y' is 3500 Å and 7000 Å, then the critical angle of x relative to y will be

The correct option is C The critical angle C is given by sin(C)=n2n1=λ1λ2⇒sin(C)=35007000=12⇒C=30∘

The wavelength of light in two liquids 'x' and 'y' is 3500 Å and 7000 Å, then

the critical angle of x relative to y will be

The correct option is C
The critical angle C is given by

$s i n (C) = \frac{n_{2}}{n_{1}} = \frac{λ_{1}}{λ_{2}} \Rightarrow s i n (C) = \frac{3500}{7000} = \frac{1}{2} \Rightarrow C = 30^{\circ}$