The wavelength of light in two liquids -x- and -y- is 3500 -A and 7000 -A- then the critical angle of x relative to y will be

Sin C=μ_2/μ_1=λ_1/λ_2=3500/7000 =1/2⇒ C=30^∘ ...

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Standard XI

Physics

TIR

The wavelengt...

Question

The wavelength of light in two liquids 'x' and 'y' is 3500 $\circ A$ and 7000 $\circ A$ , then the critical angle of x relative to y will be

60^{\circ}

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45^{\circ}

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30^{\circ}

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15^{\circ}

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Solution

The correct option is C $30^{\circ}$
$s i n C = \frac{μ_{2}}{μ_{1}} = \frac{λ_{1}}{λ_{2}} = \frac{3500}{7000} = \frac{1}{2} \Rightarrow C = 30^{\circ}$

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The wavelength of light in two liquids 'x' and 'y' is 3500 ∘A and 7000 ∘A, then the critical angle of x relative to y will be

The correct option is C 30∘sinC=μ2μ1=λ1λ2=35007000=12⇒C=30∘

The wavelength of light in two liquids 'x' and 'y' is 3500 $\circ A$ and 7000 $\circ A$ , then the critical angle of x relative to y will be

The correct option is C $30^{\circ}$
$s i n C = \frac{μ_{2}}{μ_{1}} = \frac{λ_{1}}{λ_{2}} = \frac{3500}{7000} = \frac{1}{2} \Rightarrow C = 30^{\circ}$