The wavelength of light of a particular colour is 5800 $˚ A$ . What is its order of magnitude in meter?

Open in App

Solution

1 Angstrom, or $1 ˚ A$ is $1 \times 10^{- 10}$ meter.
So, $5800 ˚ A$ = $5.8 \times 10^{3} \times 10^{- 10}$ meter = $5.8 \times 10^{- 7}$ meter.
Hence its magnitude in meter is $10^{- 7} m$

Suggest Corrections

Similar questions

Q. The wavelength of light is 589 nm. What is its order of magnitude in metre?

Q. For a colour of light, the wavelength in air is

6000 \circ A

and water is

4500 \circ A

. What will be the speed of light in water?

Q. A compound absorb light in the wavelength region 490-500 nm. Its complementary colour is :

The wavelength of light is 589 nm. What is its wavelength in A $^{\circ}$ ?

A mixture of yellow light of wavelength 580nm and blue light of wavelength 450nm is incident normally on an air film of thickness 2.9x10^2 nm. The colour of the first order of reflected light is

A. Red

B. Blue

C. Violet

D. Yellow

Please also explain what is meant by first order reflected light and how the answer is B.

Join BYJU'S Learning Program

The wavelength of light of a particular colour is 5800 ˚A. What is its order of magnitude in meter?

1 Angstrom, or 1˚A is 1×10−10meter.So, 5800˚A = 5.8×103×10−10meter = 5.8×10−7meter.Hence its magnitude in meter is 10−7m

The wavelength of light of a particular colour is 5800 $˚ A$ . What is its order of magnitude in meter?

1 Angstrom, or $1 ˚ A$ is $1 \times 10^{- 10}$ meter.
So, $5800 ˚ A$ = $5.8 \times 10^{3} \times 10^{- 10}$ meter = $5.8 \times 10^{- 7}$ meter.
Hence its magnitude in meter is $10^{- 7} m$