The wavelength of light wave of wave number $4000 {c m}^{- 1}$ is:

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Solution

We know that

Wave number is inversely proportional to wavelength.

So,

$w a v e l e n g t h = \frac{1}{w a v e n u m b e r}$

$w a v e n u m b e r = 4000 c m^{- 1}$ (given)

$w a v e l e n g t h = \frac{1}{4000}$

$\Rightarrow 0.00025 c m^{- 1}$

$\Rightarrow 2.5 \times 10^{- 4} c m^{- 1}$
This is required solution.

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