The wavelength of maximum emitted energy of a body at 700 K is 4.08 $μ$ m. If the temperature of the body is raised to 1400 K, the wavelength of maximum emitted energy will be

1.02 μm

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16.32 μm

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8.16 μm

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2.04 μm

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Solution

The correct option is D
2.04 μm

$T_{1} λ_{m_{1}} = T_{2} λ_{m_{2}} \Rightarrow λ_{m_{2}} = \frac{T_{1} λ_{m_{1}}}{T_{2}} = 4.08 \times \frac{700}{1400} = 2.04 m$

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The wavelength of maximum emitted energy of a body at 700 K is 4.08 μ m. If the temperature of the body is raised to 1400 K, the wavelength of maximum emitted energy will be

The correct option is D 2.04 μm T1λm1=T2λm2⇒λm2=T1λm1T2=4.08×7001400=2.04m

The wavelength of maximum emitted energy of a body at 700 K is 4.08 $μ$ m. If the temperature of the body is raised to 1400 K, the wavelength of maximum emitted energy will be

The correct option is D
2.04 μm

$T_{1} λ_{m_{1}} = T_{2} λ_{m_{2}} \Rightarrow λ_{m_{2}} = \frac{T_{1} λ_{m_{1}}}{T_{2}} = 4.08 \times \frac{700}{1400} = 2.04 m$