Question

The wavelength of maximum energy radiation released during an atomic explosion is $2.93\times {10}^{-10}\text{m}$. The maximum temperature attained must be of the order of
[Take $b=2.93\times {10}^{-3}\text{m-K}$]

• A. ${10}^{-7}\text{K}$
• B. ${10}^7\text{K}$
• C. ${10}^{-13}\text{K}$
• D. ${10}^6\text{K}$

Answer 1

The correct option is B ${10}^7\text{K}$

According to Wien's displacement law,
${\lambda }_m\propto \frac{1}{T}\Rightarrow {\lambda }_m=\frac{b}{T}$
From this we can say that
$T=\frac{b}{{\lambda }_m}$
From the data given in the question,
$T=\frac{2.93\times {10}^{-3}}{2.93\times {10}^{-10}}={10}^7\text{K}$
Thus, option (b) is the correct answer.