Question

The wavelength of maximum energy released during an atomic explosion was $2.93\times {10}^{-10}m$. The maximum temperature attained must be :

(Weins constant $=2.93\times {10}^{-3}mK$)

• A. $5.86\times {10}^{7}K$
• B. ${10}^{-13}K$
• C. ${10}^{-7}K$
• D. ${10}^{7}K$

Answer 1

The correct option is D ${10}^{7}K$

${\lambda }_m\times T=b$ (Wein's displacement Law)
$T=\frac{2.93\times {10}^{-3}}{2.93\times {10}^{-10}}={10}^{7}K$