The wavelength of sound source at rest is 120 cm. The source is moving with respect to the medium with velocity 60 m/s towards an observer. The wavelength of waves reaching the observer will be ____. (Given, speed of sound = 330 m/s)

98 cm

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140 cm

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120 cm

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144 cm

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Solution

The correct option is B 98 cm
$λ^{'} = (\frac{V - V_{S}}{V}) λ$

$= (\frac{330 - 60}{330}) 120$
$= 98 c m$

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The wavelength of sound source at rest is 120 cm. The source is moving with respect to the medium with velocity 60 m/s towards an observer. The wavelength of waves reaching the observer will be ____. (Given, speed of sound = 330 m/s)

The correct option is B 98 cmλ′=(V−VSV)λ =(330−60330)120 =98 cm

The correct option is B 98 cm
$λ^{'} = (\frac{V - V_{S}}{V}) λ$

$= (\frac{330 - 60}{330}) 120$
$= 98 c m$