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Question

The wavelength of the first line in Balmer series in the hydrogen spectrum is λ. What is the wavelength of the second line?
 


Correct Answer
A
2027λ
Your Answer
B
316λ
Your Answer
C
536λ
Your Answer
D
34λ

Solution

The correct option is B 2027λ
The first line in Balmer series corresponds to n=3.
1λ=R(122132)=R(1419)=5R36
λ=365R
For the second line, n=4.
1λ=R(122142)=R(14116)=3R16
λ=163R
Now, λλ=163R×5R36=2027λ=2027λ
Hence, the correct choice is (a).

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