The wavelength of the first line of Lyman series in hydrogen atom is $1216 ˚ A$ . The wavelength of the first line of Lyman series for $10 t i m e s$ ionized sodium atom will be added

0.1 ˚ A

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1000 ˚ A

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100 ˚ A

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10 ˚ A

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Solution

The correct option is A $10 ˚ A$
For Hydrogen, $Z = 1$
For Sodium, $Z = 11$
So, $λ_{N a} = \frac{λ_{H}}{Z^{2}}$
$λ_{N a} = \frac{1216}{11^{2}}$
$λ_{N a} = 10 ˚ A$

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The wavelength of the first line of Lyman series in hydrogen atom is 1216˚A. The wavelength of the first line of Lyman series for 10 times ionized sodium atom will be added

The correct option is A 10˚AFor Hydrogen, Z=1For Sodium, Z=11So, λNa=λHZ2 λNa=1216112 λNa=10 ˚A

The wavelength of the first line of Lyman series in hydrogen atom is $1216 ˚ A$ . The wavelength of the first line of Lyman series for $10 t i m e s$ ionized sodium atom will be added

The correct option is A $10 ˚ A$
For Hydrogen, $Z = 1$
For Sodium, $Z = 11$
So, $λ_{N a} = \frac{λ_{H}}{Z^{2}}$
$λ_{N a} = \frac{1216}{11^{2}}$
$λ_{N a} = 10 ˚ A$