The wavelength of the first member of Balmer series is 6563∘A. Calculate the wavelength of second member of Lyman series.
A
1025.5∘A
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B
2025∘A
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C
6563∘A
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D
None of these
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Solution
The correct option is A1025.5∘A The first orbital of Balmer series corresponds to the transition from 3 to 2 and the second member of Lyman series corresponds to the transition from 3 to 1.
Let us write the expression for the wavelength for the first member of the Balmer series.