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Question

The wavelength of the photon emitted by a hydrogen atom when an electron makes a transition from n=2 to n=1 state is:

A
194.8 nm
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B
490.7 nm
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C
913.3 nm
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D
121.8 nm
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Solution

The correct option is D 121.8 nm
ΔE=10.2 eV is the energy difference between the state n=2 and n=1.

ΔE=3.4(13.6)=10.2 eV

hcλ=10.2 eV

λ=hc10.2e m
where, e=1.6×1019 J/V

λ=1240010.2 Å
(because hc=12400 eV.A)
λ121.8 nm

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