Question

The wavelength of the radiation emitted, when in a hydrogen atom electron falls from infinity to stationary state, would be: [Rydberg constant = $1.097\times {10}^7{m}^{-1}$]

• A. $91nm$
• B. $192nm$
• C. $406nm$
• D. $9.1\times {10}^{-8}nm$

Answer 1

The correct option is A $91nm$

$\frac{1}{\lambda }=R_H[\frac{1}{\infty }-\frac{1}{1}]$

$\therefore \lambda =\frac{1}{R_H}$

$\Rightarrow \frac{1}{1.097\times {10}^7}m$

$\Rightarrow 9.1\times {10}^{-8}m$

$\Rightarrow 91\times {10}^{-9}m$

$=91nm$

Hence, option A is correct.