The wavelength of two sound waves are 34.5cm and 34.7cm respectively. If the room temperature is 27∘C, then the frequency of beats produced by them is approximately: (velocity of sound in air at 27∘C=340m/s)
A
2 Hz
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B
5 Hz
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C
8 Hz
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D
10 Hz
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Solution
The correct option is B5 Hz Given that λ1=34.5cm=34.5×10−2 m λ2=34.7cm=34.7×10−2 m
Speed of sound v=340m/s
So, from formula, f1=vλ1=34034.5×10−2=985.5≈985Hz
and f2=vλ2=34034.7×10−2=979.83≈980Hz
So
Beat frequency =f1−f2=985−980=5Hz