The wavelength range of the visible spectrum extends from violet $(400 n m)$ to red $(750 n m)$ . Express these wavelengths in frequencies $(H z)$ . $(1 n m = 10^{- 9} m)$

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Solution

$F r e q u e n c y o f v i o l e t l i g h t, v = \frac{c}{λ} = \frac{3.00 \times 10^{8} m s^{- 1}}{400 \times 10^{- 9} m} = 7.50 \times 10^{14} H z F r e q u e n c y o f r e d l i g h t, v = \frac{c}{λ} = \frac{3.00 \times 10^{8} m s^{- 1}}{680 \times 10^{- 9} m} = 4.41 \times 10^{14} H z$

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The wavelength range of the visible spectrum extends from violet (400 nm) to red (750 nm). Express these wavelength in frequencies (Hz). $(1 n m = 10^{- 9} m)$ .

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The wavelength range of the visible spectrum extends from violet (400 nm) to red (750 nm). Express these wavelengths in frequencies (Hz). (1 nm=10−9m)

Frequencyofvioletlight,v=cλ=3.00×108ms−1400×10−9m=7.50×1014HzFrequencyofredlight,v=cλ=3.00×108ms−1680×10−9m=4.41×1014Hz

The wavelength range of the visible spectrum extends from violet $(400 n m)$ to red $(750 n m)$ . Express these wavelengths in frequencies $(H z)$ . $(1 n m = 10^{- 9} m)$

$F r e q u e n c y o f v i o l e t l i g h t, v = \frac{c}{λ} = \frac{3.00 \times 10^{8} m s^{- 1}}{400 \times 10^{- 9} m} = 7.50 \times 10^{14} H z F r e q u e n c y o f r e d l i g h t, v = \frac{c}{λ} = \frac{3.00 \times 10^{8} m s^{- 1}}{680 \times 10^{- 9} m} = 4.41 \times 10^{14} H z$