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Question

The wavenumber of last line of Lyman series of hydrogen spectrum is 109674 cm1. The wave number of Hα line in Balmer series He+ is :

A
438696 cm1
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B
106974 cm1
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C
30465 cm1
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D
60930 cm1
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Solution

The correct option is D 60930 cm1
For last line of Lyman series of H Spectrum;
Z=1,n1=1,n2=
We know,
¯v=RZ2[1n211n22]
So, according to the question
109674=R×1[11212]
R=109674 cm1

For Hα line in Balmer series of He+;Z=2,n1=2,n2=3
Substitting the values we get,
¯v=109674×22[122132]
¯v=109674×22[536]
On solving, we get
¯v=60930 cm1

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