wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The waves associated with matter is called matter waves. Let λe and λp be the de-Broglie wavelengths associated with electron and proton respectively. If they are accelerated by same potential, then

A
λe>λp
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
λp>λe
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
λp=λe
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
λe=1λp
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B λe>λp
The de-Broglie wavelength of a charged particle (e) of mass m , accelerated through potential V is given by
λ=h/2meV
For electron ,
λe=h/2meeeV ............................eq1
For proton ,
λp=h/2mpepV ...........................eq2
Dividing eq1 by eq2 ,
λeλp=mpepmeee
Now , me=mp
Hence , λeλp=mpme
As mp>me
therefore λe>λp

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Emission and Absorption Spectra
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon