The weakest base among the following is

H^{-}

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{C H}_{3}^{-}

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{C H}_{3} O^{-}

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{C l}^{-}

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Solution

The correct option is D ${C l}^{-}$
$H^{-} + H^{+} \to H_{2}$

$C H_{3}^{-} + H^{+} \to C H_{4}$

$C H_{3} O^{-} + H^{+} \to C H_{3} O H$

$C l^{-} + H^{+} \to H C l$

$H C l$ is the strongest acid thus $C l^{-}$ is the weakest base among the given ions.

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Similar questions

Arrange in their increasing order of equilibrium constants for hydration.

C H_{3} - O | | C - C H_{3} (A), C H_{3} - O | | C - H (B), C H_{3} - O | | C - C H_{2} - C l (C), H - O | | C - H (D), C l - C H_{2} - O | | C - H (E)

Q. Strongest and weakest acid among the following:
I:

{C H}_{3} - {N O}_{2}

; II:

{C H}_{2} - C H O

; III:

{C H}_{3} - F

; IV:

{C H}_{3} - C H

Which of the following is not correct?

$O r d e r o f b a s i c i t y O r d e r o f n u c l e o p h i l i c i t y (a) F^{-} > C l^{-} > B r^{-} B r_{-} > C l^{-} > F^{-} (b) H - O - O^{-} > O H^{-} H - O - O^{-} > O H^{-} (c) C H_{3} > N H_{2}^{-} > O H - C H_{3} > N H_{2}^{-} > O H^{-} (d) H_{2} O > H_{2} S H_{2} O < H_{2} S$