Question

The weekly wages (in $Rs.$) of $30$ workers in a factory are.

$830,835,890,810,835,836,869,845,898,890,820,860,832,$ $833,855,845,804,808,812,840,885,835,835,836,$ $878,840,868,890,806,840$

Using tally marks make a frequency table with intervals as $800-810,810-820$ and so on.

Answer 1

Given data:

$830,835,890,810,835,836,869,845,898,890,820,860,$ $832,833,855,845,804,808,812,840,885,835,835,836,$ $878,840,868,890,806,840$

In data,

Minimum value $=804$ and Maximum value $=898$

i.e data is lying between $800$ and $900$.

Now, we have to prepare the a frequency table with intervals as $800-810,810-820$ till $890-900$.

Lets count the number of observations in each class interval and write a symbol '$|$' (Tally mark) for each observation(number). If the count reach to $5$ then write as $||||$.

Represent a numerical value for each tally marks in every class interval. Which is known as Frequency.

Example:

In class interval $830-840$, select the observations from $830$ to below $840$. Since, $840$ need to count in next class interval.

Observations are $830,835,835,836,832,833,835,835,836,$

Here for each observation, need to write a tally mark.

which are $||||||||$

In frequency column, count the lines and write its numerical value. i.e $9$.

Now lets start to make the frequency table,

A frequency distribution table by using tally marks for the above data is as follows.

The upper limit of the class will not be included in the class intervals.

$\begin{array}{ccc}\text{Interval}& \text{Tally Marks}& \text{Frequency}\\ 800-810& |||& 3\\ 810-820& ||& 2\\ 820-830& |& 1\\ 830-840& ||||||||& 9\\ 840-850& ||||& 5\\ 850-860& |& 1\\ 860-870& |||& 3\\ 870-880& |& 1\\ 880-890& |& 1\\ 890-900& ||||& 4\\ \text{Total}& & 30\end{array}$