Question

The weight (in-grams) of ${AgNO}_3$ present in 100 ml of 0.25 M solution :

• A. $4.25$
• B. $2$
• C. $17$
• D. $1.7$

Answer 1

The correct option is A $4.25$

$Molarity=\frac{Weight}{Molecularweight}\times \frac{1000}{V\left(ml\right)}$

$0\cdot 25=\frac{Weight}{170}\times \frac{1000}{100}$

$weight=17\times 0\cdot 25$

$=4\cdot 25gm$