The weight of a balloon is $W_{1}$ when empty and $W_{2}$ when filled with air. Both are weighed in air by the same sensitive spring balance and under identical condition. Then

W_{1} = W_{2}

, as the weight of air in the balloon is offset by the force of buoyancy on it

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W_{2} < W_{1}

, due to the force of buoyancy acting on the filled balloon

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W_{2} > W_{1}

as the air inside is of a greater pressure and hence has greater density than the air outside

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W_{2} = W_{1} +

weight of the air inside it

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Solution

The correct option is C $W_{2} > W_{1}$ as the air inside is of a greater pressure and hence has greater density than the air outside
The air inside the balloon is at higher pressure. inside (density) the ballon is higher. it's not compensating the buoyant force due to outside (density of air outside)
$W_{2} > W_{1}$

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The weight of a balloon is W1 when empty and W2 when filled with air. Both are weighed in air by the same sensitive spring balance and under identical condition. Then

The correct option is C W2>W1 as the air inside is of a greater pressure and hence has greater density than the air outsideThe air inside the balloon is at higher pressure. inside (density) the ballon is higher. it's not compensating the buoyant force due to outside (density of air outside)W2>W1

The weight of a balloon is $W_{1}$ when empty and $W_{2}$ when filled with air. Both are weighed in air by the same sensitive spring balance and under identical condition. Then