Given that,
Weight of body in air = 100 N
Buoyant force = Weight of liquid displaced
Volume of water displaced = 400 cc2
Density of water = 1g/cm3
In this case,
ρ=mV
m=ρ×V
m=1×400
m=400g
We know that,
The weight of water displaced is
W=m×g
W=25×9.8
W=3.92N
Now, weight of the object in water
W=100−3.92
W=96.08
W=96N
Hence, the weight of object in water is 96 N