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Question

The weight of a mixture containing HCl  and H2SO4 is 0.1 g. On treatment with an excess of an AgNO3 solution, the acid mixture gives 0.1435 g of AgCl. Weight percentage of the H2SO4 in the mixture is: (Molecular mass of H, Cl, S, O, Ag, N are 1 u, 35.5 u, 32 u, 16 u 108 u,and 14 u)


Solution

AgNO3 reacts with HCl to give AgCl.
AgNO3+HClAgCl+HNO3
Given, mass of  AgCl=0.1435 g
moles of AgCl=0.1435143.5=103 mol
Accroding to the stoichiometry,
Moles of AgCl = moles of HCl
Hence Moles of HCl=103 mol
Mass of HCl=36.5×103=0.0365 g
So, mass of H2SO4=(0.10.0365) g=0.0635 g
weight % of H2SO4=.0635×1000.1=63.5%

Chemistry

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