The weight of a person is $60 k g$ . If he gets $10^{5}$ calories heat through food and the efficiency of his body is $28 %$ then upto how much height he can climb when he use entire energy gained in climbing.

100 m

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200 m

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400 m

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1000 m

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Solution

The correct option is B $200 m$
$e_{g}$ = energy gained = $10^{5}$ calorie
$e_{u}$ = energy used = n eg
n = efficiency = 0.28
energy used = $0.28 \times 10^{5}$
= 28000 calorie.
$e_{u} = m g h$
$28000 \times 4.2 j o u l e = 60 \times 10 \times h$
$h = 199 m \approx 200 m$
So option B.

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A rock climber climbs a hill at the rate of 3 m/s. If he starts climbing from 20 m above the ground surface, how much time will he take to climb the hill which is 200m in height? [3 MARKS]

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The weight of a person is 60 kg. If he gets 105 calories heat through food and the efficiency of his body is 28% then upto how much height he can climb when he use entire energy gained in climbing.

The correct option is B 200meg = energy gained = 105 calorieeu = energy used = n egn = efficiency = 0.28energy used = 0.28×105= 28000 calorie.eu=mgh28000×4.2joule=60×10×hh=199m≈200mSo option B.

The weight of a person is $60 k g$ . If he gets $10^{5}$ calories heat through food and the efficiency of his body is $28 %$ then upto how much height he can climb when he use entire energy gained in climbing.

The correct option is B $200 m$
$e_{g}$ = energy gained = $10^{5}$ calorie
$e_{u}$ = energy used = n eg
n = efficiency = 0.28
energy used = $0.28 \times 10^{5}$
= 28000 calorie.
$e_{u} = m g h$
$28000 \times 4.2 j o u l e = 60 \times 10 \times h$
$h = 199 m \approx 200 m$
So option B.