The weight of a rider, driving scooter is assumed to be evenly distributed on both the tyres. The area of contact of each tyre with the ground is 10cm2. If the pressure inside the tyres is 2 bar, find the mass of the rider. (g=10ms−2)
A
40 kg
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B
50 kg
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C
60 kg
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D
70 kg
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Solution
The correct option is A40 kg Area of contact of each tyre =10cm2 Area of contact of two tyres (A) =2×10cm2=20cm2 =20×10−4m2(∴1cm2=10−4m2) Pressure(P)=2bar=2×105Pa(∴1bar=105Pa)
Weight of the person=pressure×area
W=P×A=2×105×20×10−4=400N
Weight of the person is 400 N. Mass of the person (m) =Wg=40010=40kg