The weight of a solid is 80g in air and 50g in a liquid of relative density 1.5. The specific gravity of the solid is -

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Solution

The correct option is A
4

Weight of solid in air =80 g
Weight of solid in liquid =50g
Loss of weight of solid in liquid =80-50 =30g
Weight of equal volume of liquid by Archimedes prinicple =30g
If the displaced liquid has a volume v $c m_{3}$ , then its weight = $v \times 1.5 = 30 g$
$V = 20 c m^{3}$
Since solid is completely immersed in liquid, so volume =v
The volume of water displaced = $20 c m^{3}$
Weight of this displace water =20g
So, we have specific gravity of solid = $= \frac{w t o f s o l i d i n a i r}{w t o f w a t e r d i s p l a c e d} = \frac{80 g}{20 g} = 4$

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