Question

The weight of $AgCl$ precipitated when a solution containing $5.85g$ of $NaCl$ is added to a solution containing $3.4g$ of $AgN{O}_3$ is:

• A. $28g$
• B. $9.25g$
• C. $2.870g$
• D. $58g$

Answer 1

Answer: (C)

$2.870g$

Balanced reactio is:

$NaCl+AgN{O}_3\to AgCl+NaN{O}_3$

molar mass of $AgN{O}_3$=170 g

molar mass of $NaCl$=58.5 g

molar mass of $AgCl$=143.5 g

from the reaction 58.5 g $NaCl$ reacts with 170 g $AgN{O}_3$

thus 5.85 g $NaCl$ will reacts with $=\frac{170}{58.5}\times 5.85=17gAgN{O}_3$

Given $AgN{O}_3$=3.4 g

therefore $AgN{O}_3$ is completely consumed and is the limiting reagent

170 g $AgN{O}_3$ produces 143.5 g $AgCl$

3.4 g will produce =$\frac{143.5}{170}\times 3.4=2.87gAgCl$

Hence, option $C$ is correct.