Question

The weight of an atom of Uranium is 238 amu. Its actual weight is ______ g.

• A. $1.43\times {10}^{26}$
• B. $3.82\times {10}^{-22}$
• C. $6.99\times {10}^{-23}$
• D. $1.53\times {10}^{-22}$

Answer 1

The correct option is B $3.82\times {10}^{-22}$

weight of one atom of uranium= $238amu$

weight of one mole of uranium= $238g$

No of atoms in one mole of uranium = $6.23\times {10}^{23}$

weight of one atom uranium in g=$\frac{238}{6.23\times {10}^{23}}$

=$3.82\times {10}^{-22}$

Hence, the correct option is $B$