Question

The weight of an empty gas cylinder is $16\frac{4}{5}$ kg and it contains $14\frac{2}{3}$ kg of gas. What is the weight of the cylinder filled with gas?

Answer 1

Weight of the cylinder filled with gas = Weight of the empty cylinder + Weight of the gas inside the cylinder
Thus, we have:
$$\begin{gathered} \left(16\frac{4}{5}+14\frac{2}{3}\right)\mathrm{kg} \\ =\left(\frac{84}{5}+\frac{44}{3}\right)\mathrm{kg}(\mathrm{L}.\mathrm{C}.\mathrm{M}.\mathrm{of}5\mathrm{and}3=(3\times 5)=15)=\left(\frac{\left(252+220\right)}{15}\right)\mathrm{kg}=\left(\frac{472}{15}\right)\mathrm{kg}=31\frac{7}{15}\mathrm{kg} \end{gathered}$$
Hence, the weight of the cylinder filled with gas is $31\frac{7}{15}\mathrm{kg}$.