Question

The weight of an object in the coal mine, sea level and at the top of the mountain are respectively ${\omega }_1,{\omega }_2,{\omega }_3$ then

• A. ${\omega }_1<{\omega }_2>{\omega }_3$
• B. ${\omega }_1={\omega }_2={\omega }_3$
• C. ${\omega }_1<{\omega }_2<{\omega }_3$
• D. ${\omega }_1>{\omega }_2>{\omega }_3$

Answer 1

The correct option is A ${\omega }_1<{\omega }_2>{\omega }_3$

For position $\left(1\right)$:

$g_1=\frac{GM}{R^3}(R-d)$, $w_1=m{g}_1$

For position $\left(2\right)$:

$g_2=\frac{GM}{R^2}$, $w_2=m{g}_2$

For position $\left(3\right)$:

$g_3=\frac{GM}{(R+h{)}^2}$, $w_3=m{g}_3$

Clearly we can see that $g_1<g_2>g_3$

Thus $w_1<w_2>w_3$ (A).