wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The weight of gaseous mixture containing 6.02×10^23molecules of nitrogen and 3.01×10^23molecuels of sulphur dioxide are

Open in App
Solution

We know that 6.02×10^23 = 1mol
slly 3.01×10^23 = .5 mol
therefore, weight of 1 mol of N2 = 2 x 14= 28g
weight of .5 mol of SO2 = molecular weight of SO2 × number of moles
= 64 × .5 = 32 g

therefore the total weight = 28 + 32 g = 60 g

flag
Suggest Corrections
thumbs-up
25
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon