The weight of gaseous mixture containing 6.02×10^23molecules of nitrogen and 3.01×10^23molecuels of sulphur dioxide are
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Solution
We know that 6.02×10^23 = 1mol slly 3.01×10^23 = .5 mol therefore, weight of 1 mol of N2 = 2 x 14= 28g weight of .5 mol of SO2 = molecular weight of SO2 × number of moles = 64 × .5 = 32 g