Question

The weight of gold formed when 1 faraday of electricity is passed through water solution of gold (III) chloride is :

• A. One gram atom of Au
• B. 2 gram atom of Au
• C. 3 gram atom of Au
• D. 1/3 gram atom of Au

Answer 1

The correct option is D 1/3 gram atom of Au

$AuC{l}_3$
$A{u}^{3+}+3e^{-}\to Au$
3 F electricity reduces 1 g atom of Au
$\therefore 1Faradayelectricityreduced\frac{1}{3}\times 1=\frac{1}{3}gramatomofAu$