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Gay Lussac's Law, Avagadro's Law

The weight of...

Question

The weight of hydrogen gas obtained from $42$ g of $C a H_{2}$ by treatment with water is _________ gm.

A

2

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B

6

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C

4

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D

8

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Solution

The correct option is C 4
Solution:- (C) $4$
Molecular weight of $C a H_{2} = 42 g$
$C a H_{2} + 2 H_{2} O \to C a {(O H)}_{2} + 2 H_{2}$
From the above reaction,
$1$ mole of $C a H_{2}$ gives $2$ moles of $H_{2}$ .
Hence $42 g$ of $C a H_{2}$ will give $4 g$ of $H_{2}$ .

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