Question

The weight of molecule of the compound $C_{60}{H}_{122}$ is:

• A. $1.4\times {10}^{-21}g$
• B. $1.09\times {10}^{-21}g$
• C. $5.025\times {10}^{23}g$
• D. $16.023\times {10}^{23}g$

Answer 1

Answer: (A)

$1.4\times {10}^{-21}g$

molar weight of molecule $C_{60}{H}_{122}=C\times 60+H\times 122=12\times 60+1\times 122=842g$

weight of 1 mole $=842g$

weight of $6.023\times {10}^{23}$ molecules = 842g

weight of 1 molecule $=\frac{842}{6.023\times {10}^{23}}$

On solving, we get $=139.797\times {10}^{-23}\approx 1.4\times {10}^{-21}g$