Question

The weight of silver (At. Wt. = 108) displaced by a quantity of electricity which displaces 5600 ml of $O_2$ at STP will be

• A. 5.4 g
• B. 10.8 g
• C. 54.0 g
• D. 108.0 g

Answer 1

The correct option is D 108.0 g

Since $22400ml$ is occupied by 1 mole of $O_2$ at STP.

$5600ml=\frac{5600}{22400}mol{O}_2=\frac{1}{4}mol{O}_2$

$\therefore$ Weight of Oxygen$=\frac{1}{4}\times 32=8g$

Equivalent of $Ag=$Equivalent of $O_2$

$=\frac{WeightofAg}{EquivalentWeightofAg}$

$=\frac{W_{O_2}}{EquivalentWeightof{O}_2}$

$\therefore W_{Ag}=\frac{W_{O_2}}{M_{O_2}}\times M_{Ag}$

$\therefore W_{Ag}=(\frac{8}{32}\times 4)\times 108$

$W_{Ag}=108gm$