The weight of white precipitate obtained when 0.1 mole of acetylene gas is passed through ammoniacal silver nitrate solution is

120g

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24g

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10.8g

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54g

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Solution

The correct option is B
24g

1 mole of $C_{2} H_{2}$ (26g) gives 240g of silver acetalide 0.1 mole of $C_{2} H_{2}$ gives ?

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The weight of white precipitate obtained when 0.1 mole of acetylene gas is passed through ammoniacal silver nitrate solution is

The correct option is B 24g 1 mole of C2H2 (26g) gives 240g of silver acetalide 0.1 mole of C2H2 gives ?

The correct option is B
24g

1 mole of $C_{2} H_{2}$ (26g) gives 240g of silver acetalide 0.1 mole of $C_{2} H_{2}$ gives ?