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Gas laws from KTG

The weight - ...

Question

The weight - volume percentage (w/v) of $10 V$ $H_{2} O_{2}$ solution is:

6

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2

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11

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3

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Solution

The correct option is D $3$ %
The volume strength of $H_{2} O_{2}$ can be converted into the weight - volume percentage (w/v) by the following expression:

The weight - volume percentage (w/v) $= \frac{68 x}{224}$ %

Where $x$ represents volume strength which in this example is $10 V$ .

The weight - volume percentage (w/v) $= \frac{68 \times 10}{224} = 3$ %

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∴, Normality of H_{2} O_{2} Solution = 2 \times Molarity of H_{2} O_{2} Solution

11.2 V H_{2} O_{2}

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What is the percentage strength $(% w / V)$ of $11.2 V$ $H_{2} O_{2}$ ?

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