The weight (W) of an object at a depth of R/4 from the surface of the earth will be (R is the radius of the earth)
A
Zero
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B
W/4
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C
W/2
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D
W
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Solution
The correct option is D W/4 The apparent acceleration due to gravity at a depth d is given by g′=g(1−d/R).Substituting d=R/4, we get g' = g/4 Thus the apparent weight becomes W/4 The correct option is (b)