Question

The weights (in kilograms) of ten puppies from the same litter are recorded below:
$1.231.422.011.561.660.921.381.441.521.48$
Calculate: the median weight

Answer 1

Given entries are $1.23,1.42,2.01,1.56,1.66,$

$0.92,1.38,1.44,1.52,1.48$

Ascending order of the entries

$0.92,1.23,1.38,1.42,1.44,1.48,1.52,1.56,1.66,2.01$

total no. of terms = 10 i.e., even

$\therefore$ median = $\frac{\frac{n}{2}+(\frac{n}{2}+1)}{2}th$ term

$=\frac{(5^{th}+6^{th})}{2}$ term = $\frac{1.44+1.48}{2}$

median = 1.46