The wheel of a cart is making 5 revolutions per sec. If the diameter of the wheel is 84cm, find its speed in km/hr. Give answer correct to the nearest km.

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Solution

1 second - 5 revolutions
1 revolution covers $π D$ distance = $\frac{84 π}{100}$ metres [ $∵$ diameter = 84 metre]
Hence 5 revolutions $= \frac{84 π}{100} \times 5$ metres/second
$S p e e d = \frac{84}{100} \times \frac{22}{7} \times 5 m / s e c = \frac{84}{100} \times \frac{22}{7} \times 5 \times \frac{3600}{1000} k m / h r$ .
$\Rightarrow S p e e d = 47.52 k m / h r$ .

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The wheel of a cart is making 5 revolutions per sec. If the diameter of the wheel is 84cm, find its speed in km/hr. Give answer correct to the nearest km.

1 second - 5 revolutions 1 revolution covers πD distance = 84π100 metres [∵ diameter = 84 metre] Hence 5 revolutions =84π100×5 metres/second Speed=84100×227×5 m/sec=84100×227×5×36001000km/hr. ⇒Speed=47.52 km/hr.