Question

The width of a rectangle is $3\frac{1}{3}\text{ft}$. The length is $2\frac{1}{4}$ times the width. What is the area of the rectangle?

• A. $\frac{10}{12}\text{sq ft}$
• B. $\frac{90}{12}\text{sq ft}$
• C. $\frac{810}{12}\text{sq ft}$
• D. $\frac{9}{12}\text{sq ft}$

Answer 1

The correct option is C $\frac{810}{12}\text{sq ft}$

Detailed step-by-step solution:
The width of the rectangle = $3\frac{1}{3}\text{ft}$

The length = $2\frac{1}{4}$ times the width = $2\frac{1}{4}\times 3\frac{1}{3}\text{ft}$

Convert $2\frac{1}{4}\text{and}4\frac{1}{3}$ in the standard form of a fraction.

$2\frac{1}{4}\text{ft}=\frac{2\times 4+1}{4}=\frac{9}{4}\text{and}3\frac{1}{3}=\frac{3\times 3+1}{3}=\frac{10}{3}\text{ft}$

The length of the rectangle =$\frac{9}{4}\text{ft}\times \frac{10}{3}\text{ft}=\frac{9\times 10}{4\times 3}\text{ft}=\frac{90}{12}\text{ft}$

The area of the rectangle =$\text{Length}\times \text{Width}=\frac{9}{4}\text{ft}\times \frac{90}{12}\text{ft}=\frac{810}{12}\text{sq ft}$