The width of a slit is 0.012 mm. Monochromatic light is incident on it. The angular position of first bright line is 5.2o. The wavelength of incident light is :(given sin5.20=0.0906)
A
6040 oA
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B
4026 oA
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C
5890 oA
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D
7248 oA
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Solution
The correct option is D 7248 oA It is one of a Fraunhoffer's diffraction from single slit. So for bright fringe where a is the width of slit. asinθ = (2n+1)λ2 λ = 2asinθ2n+1 = 2×1.2×10−5×0.09062×1+1 =7248×10−10 m =7248oA