Question

The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. Find the upper class limit of the highest class.
[2 Marks]

Answer 1

If the width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10.
Class width = Upper limit - lower limit
The upper limit of first class = 10 + 5 = 15. [1 Mark]
So the class intervals are:
10 - 15
15 - 20
20 - 25
25 - 30
30 - 35 [1 Mark]
The upper limit of the fifth class is 35.

OR

The upper limit of the fifth class = 15 + 4 $\times$ 5 = 35. [2 Marks]