The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. The upper limit of the highest class is

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Solution

The correct option is C 35
If the width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10, then the upper limit of the highest class can be found as follows:
The upper limit of first class = 10+5=15
The upper limit of the fifth class=15 + 4 x 5 = 35.

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Q. The width of each of five continuous classes in frequency distribution is 5 and lower class limit lowest class is 10. What is the upper class limit of the highest class ?

Question 4
The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. The upper class limit of the highest class is:

A) 15
B) 25
C) 35
D) 40

Q. The width of each of the five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. The upper class limit of the highest class is
(a) 45
(b) 25
(c) 35
(d) 40

Choose the correct answer in each of the following questions:
The width of each of the five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. The upper class limit of the highest class is
(a) 45
(b) 25
(c) 35
(d) 40

(i) Find the class mark of the class 90-120.
(ii) In a frequency distribution, the mid-value of the class is 10 and width of the class is 6. Find the lower limit of the class.
(iii) The width of each of five continuous classes in a frequency distribution is 5 and lower class limit of the lowest class is 10. What is the upper class limit of the highest class?
(iv) The class marks of a frequency distribution are 15, 20, 25, .... Find the class corresponding to the class mark 20.
(v) In the class intervals 10-20, 20-30, find the class in which 20 is included.

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