Question

The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10 The upper class limit of the highest class is

• A. 25
• B. 30
• C. 35
• D. 50

Answer 1

The correct option is C 35

$\Rightarrow$ Let $x$ and $y$ be the upper and lower class limit of frequency distribution.

$\Rightarrow$ width of the class = $5$

$\Rightarrow$ $x-y=5$ ---- ( 1 )

$\Rightarrow$ Also, given lower class $y=10$. On putting $y=10$ in Eq.( 1 ), we get,

$\Rightarrow$ $x=15$

$\Rightarrow$ So, the upper class limit of the lowest class is $15.$

$\Rightarrow$Hence, the upper class limit of the highest class=(Number of continuous classes x Class width + Lower class limit of the lowest class)

$\Rightarrow$ The upper class limit of the highest class = $5\times 5+10=25+10=35$

$\therefore$ The upper class limit of the highest class is $35.$