The width of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. Find the upper class limit of the highest class.

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Solution

Given: Width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10.
Class width = Upper limit - lower limit
The upper limit of first class = 10 + 5 = 15
So the class intervals are:
10 - 15
15 - 20
20 - 25
25 - 30
30 - 35
The upper limit of the fifth class is 35.
(or)
The upper limit of the fifth class
= 15 + 4 x 5 = 35

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Question 4
The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. The upper class limit of the highest class is:

A) 15
B) 25
C) 35
D) 40

(i) Find the class mark of the class 90-120.
(ii) In a frequency distribution, the mid-value of the class is 10 and width of the class is 6. Find the lower limit of the class.
(iii) The width of each of five continuous classes in a frequency distribution is 5 and lower class limit of the lowest class is 10. What is the upper class limit of the highest class?
(iv) The class marks of a frequency distribution are 15, 20, 25, .... Find the class corresponding to the class mark 20.
(v) In the class intervals 10-20, 20-30, find the class in which 20 is included.

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