You visited us 6 times! Enjoying our articles? Unlock Full Access!

Dependence on Area and Orientation

The wire loop...

Question

The wire loop shown in figure carries a current as shown. The magnetic field at the centre O is:

zero

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{μ_{0} i}{4} (\frac{1}{R_{1}} - \frac{1}{R_{2}})

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{μ_{0} i}{4} (\frac{1}{R_{1}} + \frac{1}{R_{2}})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{μ_{0} i}{2} (\frac{1}{R_{1}} - \frac{1}{R_{2}})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\frac{μ_{0} i}{4} (\frac{1}{R_{1}} - \frac{1}{R_{2}})$
As shown in figure,the field due to smaller radius $R_{1}$ circular wire is outward but due to larger radius $R_{2}$ field is into the plane.
Now net field of 0 is $B$
$B = \frac{μ_{0} i}{4 R_{1}} - \frac{μ_{0} i}{4 R_{2}}$
$B = \frac{μ_{0} i}{4} (\frac{1}{R 1} - \frac{1}{R 2})$

Suggest Corrections

Similar questions

Q. A wire loop PQRSP is constructed by joining two semi-circular coils of radius

r_{1}

and

r_{2}

respectively, as shown in the figure. If the current flowing in the loop is I, then the magnetic induction at the point O is:

Q. In the figure shown there are two semicircles of radii

r_{1}

and

r_{2}

in which a current I is flowing. The magnetic induction at the centre O will be:

In the figure shown there are two semicircles of radii $r_{1}$ and $r_{2}$ in which a current i is flowing. The magnetic induction at the centre O will be

Q. The wire loop

P Q R S P

formed by joining two semicircular wires of radii

R_{1}

and

R_{2}

carries a current

I

as shown in figure. If the magnitude of the magnetic induction at centre

C

\frac{μ_{0} I}{x} [\frac{1}{R_{1}} \frac{I}{R_{2}}]

. find x.

Q. A wire loop formed by joining two semicircular wires of radii

R_{1}

and

R_{2}

carries a current

I

as shown in the following diagram. The magnetic induction at the centre

O

is :

Join BYJU'S Learning Program

The wire loop shown in figure carries a current as shown. The magnetic field at the centre O is:

The correct option is B μ0i4(1R1−1R2)As shown in figure,the field due to smaller radius R1 circular wire is outward but due to larger radius R2 field is into the plane.Now net field of 0 is BB=μ0i4R1−μ0i4R2B=μ0i4(1R1−1R2)