The wire of resistance R1 and R2 have temperature coefficient of resistance α1 and α2 respectively. These are joined in series. The effective temperature coefficient of resistance is
A
α1+α22
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B
√α1α2
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C
α1R1+α2R2R1+R2
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D
√R1R2α1α2√R21+R22
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Solution
The correct option is Cα1R1+α2R2R1+R2 R=R0[1+αΔT]Requ=R1+R2ΔRequ=ΔR1+ΔR2R0equαequΔT=R1α1ΔT+R2α2ΔT,asΔ=R0αΔT.αequ=R1α1+R2α2R0equ=R1α1+R2α2R1+R2