The wire shown in Fig, carries a current of $10 A$ . Determine the magnitude of magnetic field at the centre $O$ . Given radius of the bent coil is $3 c m$ .

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Solution

Given that,

Current $i = 10 A$

Radius $r = 3 c m$

Angle $θ = 360^{0} - 90^{0} = 270^{0}$

We know that,

The magnetic field

$B = \frac{μ_{0} I θ}{4 π r}$

$B = \frac{10^{- 7} \times 10 \times 3 π}{3 \times 10^{- 2} \times 2}$

$B = \frac{π}{2} \times 10^{- 4}$

$B = 1.57 \times 10^{- 4} T$

Hence, the magnetic field is $1.57 \times 10^{- 4} T$

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The wire shown in Fig, carries a current of 10 A. Determine the magnitude of magnetic field at the centre O. Given radius of the bent coil is 3 cm.

Given that, Current i=10A Radius r=3cm Angle θ=3600−900=2700 We know that, The magnetic field B=μ0Iθ4πr B=10−7×10×3π3×10−2×2 B=π2×10−4 B=1.57×10−4T Hence, the magnetic field is 1.57×10−4T

The wire shown in Fig, carries a current of $10 A$ . Determine the magnitude of magnetic field at the centre $O$ . Given radius of the bent coil is $3 c m$ .