1
Question
The work done by 100 calorie of heat in isothermal expansion of ideal gas is:
The work done by 100 calorie of heat in isothermal expansion of ideal gas is:
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Solution
The correct option is A −418.4 J
From the first law of thermodynamics
△U=q+w\triangle U=q+w△U=q+w
Here, ΔU=0 , since process is isothermal.
q=−wq=-wq=−w
w=−100 calw=-100~calw=−100 calWorkdone by the system i.e w= -ve
∴w=100cal
So work done will be 100 calorie
1 cal=4.184 J
So work done = 100×4.184 J=418.4 J
From the first law of thermodynamics
△U=q+w\triangle U=q+w△U=q+w
Here, ΔU=0 , since process is isothermal.
q=−wq=-wq=−w
w=−100 calw=-100~calw=−100 cal
Workdone by the system i.e w= -ve
∴w=100cal
So work done will be 100 calorie
1 cal=4.184 J
So work done = 100×4.184 J=418.4 J
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